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Soppose potential energy between electro...

Soppose potential energy between electronand proton at seperation `r` is given by `U = klog r, where k` is a constant. For such a hypothetical hydrogen atom , calculate the radins of nth Bohr and its energy level

A

`(2 nh)/(pi sqrt(mk))`

B

`(nh)/(2 pi sqrt(2 mk))`

C

`(nh)/(2 pi sqrt(mk))`

D

`(nh)/(4 pi sqrt(mk))`

Text Solution

Verified by Experts

The correct Answer is:
C

For a conservative force field.
`(dU)/(dr) = F`
Since `U = k log r`
`(dU)/(dr) = - (k)/( r) = F`
This force `F = -k//r` provides the centripetal force for the circular motion of electron
`(mv^(2))/( r) = (k)/( r)`
Applying Bohr's quantization rule,
`mvr = (nh)/(2 pi)`
From Eqs. (i) and (ii), we get
`r = (nh)/(2 pi sqrt(mk))`
From Eq. (i),
KE of electron `= (1)/(2) k`
Total energy of electron `= KE + PE`
PE of electron `= k log r`
`= (1)/(2) k + k loh r`
`E = (K)/(2) [1 + log (n^(2) h^(2))/(4 pi^(2)mk)]`
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