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The average lifetime for the n = 3 excit...

The average lifetime for the `n = 3` excited state of a hydrogen-like atom is `4.8 xx 10^(-8) s` and that for the `n = 2` state is `12.8 xx 10^(-8) s`. The ratio of average number of revolution made in the `n = 3` sate before any transition can take place from these state is.

Text Solution

Verified by Experts

The correct Answer is:
9
Numbersof revolution before transition = `"frequency"` xx times
Also, ` "frequency" prop (1)/(n^(3))`
`"So required ratio" = ((1//2) 12.8 xx 10^(-8))/((1//3) 4.8 xx 10^(-8)) = 9`
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