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Calculate the total energy released if 1...

Calculate the total energy released if `1.0 kg` of `.^(235)U` undergoes fission, taking the disintergration energy per event to be `Q=208 MeV` (a more accurate value than the estimate given previously).

Text Solution

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We need to know the number of nuclei in `1.00 kg` of uranium. Because `A=235`, the number of nuclei is
`N=((6.02 xx 10^(23) "nuclei mol"^(-1))/(235 g mol^(-1))) (1.00 xx 10^(3) g)`
`=2.56 xx10^(24) nuclei`
Hence, the disintergration energy is
` E=nQ =(2,56 xx 10^(24) "nuclei") (("208 89MeV")/("nucleus"))`
Because `1 MeV` is equivalent to `4. 45 xx 10^(20) kWh, E=2.3.7xx10^(7) kWh`. This is enough energy to keep a `100 W` light buth burning for about `30000 years`.
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