How many electrons protons, and neutrons are there in `12 g` of `._(6) C^2` and in `14g` of `._(6) C^(14)` ?.

Explanation

Mass number (or atomic weight)of `_(6)C^(12)` is 12.
Therefore, the number of atoms is 12 g of `_(6)C^(12)`
`=Avogadro number =6xx 10^(3)`
The number of electrons in 12 g of `_(6)C^(12)`
` =6 xx 6 xx 10^(23)=36xx10^(23)`
The number of protons in 12 g of `._(6)C^(12)`
`=36 xx 10^(23)`
The number of neutrons in `12 g` of `._6C^(12)`
`(A-Z) xx 6 xx 10^(23) =(12-6) xx 6 xx 10^(23)`
`=36 xx 10^(23)`
Similarly,number of electrons in `14 g` of `._6C^(14)`
`=3.6 xx10^(23)`
number of protrons in `14 g` of `._(6)C^(14)`
`(A -Z) xx 6 xx 1023`
`(14-6)xx 6xx1023=48xx1023`.
The emitted particels are `alpha,beta,beta,alpha and alpha` respectively. The processess may be expressed as
`._(92)U^(238))rarr(._(90)Th ^(234)) +(._2He^4) (alpha-particles)`
`(._(90)Th^(234))rarr.(_(91)Pa ^(234)) +(._(-1)beta^(2)) (beta-particles)`
`(._(91)Pa^(234))rarr(._(92)U^(234)) +(._(-1)beta) (beta-particles)`
`(._(92)U^(234))rarr(._(90)Th^(230)) +(._(2)He) (alpha-particles)`
`(._(90)Th^(230))rarr(._(88)Ra^(226)) +(._(2)He^(4)) (alpha-particles)` .