A tritrium gas target is bombared with a beam of monoenergetic protons of kinetic energy `K_(1) =3 MeV` The `KE` of the neutron emiited at `30^(@)` to the inicdent beam is `K_(2)` ? Find the value of `K_(1)//K_(2)` (approximately in whole number). Atomic masses are `H^(1) =1.007276 amu`, `n^(1)=1.008665 amu`, `._1 H^3=3.016050 amu`, `._2He^3=3.016030 amu`.

Answer

`2`

Explanation

Nuclear reaction is `._(1)H^(1) +._(1)H^(3) rarr ._(2)He^(3) +_(0)n^(1)+Q`
`Q=-1.2745 MeV`
Using conservation of linear momnetum, we get
`K_(2) =1.44 MeV, K_(1) =3 MeV` .