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The radioactive of a sample is R(1) at a...

The radioactive of a sample is `R_(1)` at a time `T_(1)` and `R_(2)` at a time `T_(2)`. If the half-life of the specimen is `T`, the number of atoms that have disintegrated in the time `(T_(2)-T_(1))` is equal to`(n(R_(1)-R_(2))T)/(ln4) `. Here n is some integral number. What is the value of n?

Text Solution

Verified by Experts

The correct Answer is:
2
`R_(1)=lambda N_(1), R_(2)=lambda N_(2)`
No of atoms decayed in `(T_(1)-T_(2))`
`=N_(1)-N_(2)=(R_(1)-R_(2))/(lambda)=((R_(1)-R_(2))T)/(ln2)=(2(R_(1)-R_(2))T)/(ln2)`
Hence `n=2`.
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