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In the final Uranium radioactive series ...

In the final Uranium radioactive series the initial nucleus is `U_(92)^(238) ` and the final nucleus is `Pb_(82)^(206)` . When Uranium neucleus decays to lead , the number of a - particle is …….. And the number of `beta` - particles emited is ……

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`._(92)^(238)U rarr. _(82)^(206)Pb + x ._2^4He +y. _(-1)^(0)e`
First, we find the number of `alpha`-particles. The change in mass number during the decay from uranium to lead is `238-206=32`. Therefore, the number of `alpha`-particels (with mass `"no". 4`) is `32//4=8`.
The change in atomic number (i.e., number of protons) taking place when `8 alpha`-particles are emitted and lead is formed `=92-(82+16)=6` which means six `beta`-particles are emitted.
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