In the option given below , let `E` denote the rest mass energy of a nucleas and `n` a neutron .The correct option is

Options

A. `E(._(92)^(236)U) gt E(._(53)^(137)I) + E(._(39)^(97)Y) + 2E(n)`
B. `E(._(92)^(236)U) lt E(._(53)^(137)I) + E(._(39)^(97)Y) + 2E(n)`
C. `E(._(92)^(236)U) lt E(._(56)^(140)Ba) + E(._(36)^(94)Kr) + 2E(n)`
D. `E(._(92)^(236)U) = E(._(56)^(140)Ba) + E(._(36)^(94)Kr) + 2E(n)`

Answer

a

Explanation

Iodine and Yttrium are medium sized nuclei and therefore have more binding energy per nucleon as compared to uranium which has a big nuclei and less BE/nucelon. In other words, Iodine and Y ttrium are more stable and therefore possess less energy and less rest mass. Also, when uranium nuclei explodes, it will convert inti I and Y nuclei having kinetic energies.