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A square loop OABCO of side of side l c...

A square loop `OABCO` of side of side `l` carries a current `i`. It is placed as shown in figure. Find the magnetic moment of loop.

Text Solution

Verified by Experts

Magnetic of dipole momentum `|vecM|=IA=Il^2`
Direction of magnetic moment is found using right hand rule.
`vecM=(cos30^@(-hatj)+sin30^@(hatj)M`
`=(Il^2)/2(-sqrt3hati+hatj)`
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