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Find the magnetic moment of the current ...

Find the magnetic moment of the current carrying loop OABCO as shown in Fig. 1.81. Given that `i=4 A, OA = 20 cm, and AB = 10 cm.`

Text Solution

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Magnetic moment of the loop
`|vecM|=iA=4.0xx20xx10xx10^-4=8xx10^-2Am^2`
For direction:

Unit vector in the direction of
`hatM=cos60^@hatj-cos30hatk=(hatj)/2-(sqrt3)/2hatk`
`:. vecM=|vecM|hatM=4xx10^-2(hatj-sqrt3hatk)Am^2`
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