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A U tube of uniform square cross-section...

A U tube of uniform square cross-sectional side a has mercury in it. Current I is passed between sealed electrodes x and y. A magnetic field `B` is applied across horizontal section perpendicular to the plane of diagram. The difference in mercury levels is [Given: `rho` = density of mercury]
.

A

`2/3 (BI)/(rho g a)`

B

`(2BI)/(rho g a)`

C

`(BI)/(rho g a)`

D

`(4BI)/(rho g a)`

Text Solution

Verified by Experts

The correct Answer is:
c
`(hrhog)a^2=Bia or h=(BI)/(rhoga)`
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