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A conducting rod of length l and mass m is moving down a smooth inclined plane of inclination `theta` with constant i is flowing in the conductor in a direction perpendicular to paper inwards. A vertically upward magnetic field `vec B` exists in space. Then, magnitude of magnetic field `vec B` is

A

`(mg)/(il) sin theta`

B

`(mg)/(il) tan theta`

C

`(mgcos theta)/(il)`

D

`(mg)/(il sin theta)`

Text Solution

Verified by Experts

The correct Answer is:
b
Magnetic force acts in the direction shown in Fig.

Rod will move downward with constant velocity if net force
on it is zero.
or `F_mcos theta=mg sin theta`
or `ilBcos theta=mg sin theta`
`:. B=((mg)/(il)) tan theta`
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