A charged particle moving along +ve x-direction with a velocity v enters a region where there is a uniform magnetic field `B_0(-hat k), from x=0 to x=d.` The particle gets deflected at an angle `theta` from its initial path. The specific charge of the particle is

Options

A. `(v cos theta)/(Bd)`
B. `(v tan theta)/(Bd)`
C. `v/(Bd)`
D. `(v sin theta)/(Bd)`

Answer

d

Explanation

`sin theta=(d//R)`

`d=R sin theta=(mv)/(qB) sin theta`
`implies q/m=(vsin theta)/(Bd)`