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A particle of specific charge q/m = pi C...

A particle of specific charge `q/m = pi C kg^-1` is projected from the origin toward positive x-axis with a velocity of `10 ms^-1` in a uniform magnetic field `vec B = -2 hat k T.` The velocity `vec v` of particle after time `t=1/12 s` will be (in `ms^-1`)

A

`5[hati+sqrt3hatj]`

B

`5[sqrt3hati+hatj]`

C

`5[sqrt3hati-hatj]`

D

`5[hati+hatj]`

Text Solution

Verified by Experts

The correct Answer is:
B

Time period, `T=(2pim)/(qB)=(2pi)/(pixx2)=1s`

Thus, particle will be at point P after `t=1/12s`
`vecv=10[cos30hati+sin30hatj]`
`vecv=10[sqrt3/2hati+1/2hatj]=5[sqrt3hati+hatj]ms^-1`
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