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A charged particle moves in a uniform ma...

A charged particle moves in a uniform magnetic field perpendicular to it, with a radius of curvature 4 cm. On passing through a metallic sheet it loses half of its kinetic energy. Then, the radius of curvature of the particle is

A

`2 cm`

B

`4 cm`

C

`8 cm`

D

`2sqrt2 cm`

Text Solution

Verified by Experts

The correct Answer is:
D

`R=(mv)/(qB) =m/(qB) sqrt((2(KE))/m)=(sqrt(2m))/(qB)sqrt(KE)`
`implies (R_1)/(R_2) (sqrt(KE))/(sqrt(KE//2)) implies R_2=(R_1)/(sqrt2)=4/(sqrt2)=2sqrt2 cm`
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