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A charged particle with velocity hatv=xh...

A charged particle with velocity `hatv=xhati+yhatj` moves in a magnetic field `vecB=yhati+xhatj`. The force acting on the particle has magnitude F. Which one of the following statements is are correct?

A

No force will act on charged particle if x=y

B

If `xgty`,f `mu(x^2-y^2)`

C

If `xgty`, the force will act along z-axis

D

If `ygtx`, the force will act along y-axis.

Text Solution

Verified by Experts

The correct Answer is:
(a,b,c)

If `x=y, the vecv||vecB, i.e., vecF_(mag)=0`
Hence (a) is correct.
`vecF_(mag)=q(vecvxxvecB)=q[(xhati+yhatj)xx(yhati+xhatj)]`
`vecF_(mag)=q(x^2-y^2)hatk`
If xgty, then the force is along z-axis.
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