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A wooden cubical block ABCDEFG of mass m...

A wooden cubical block ABCDEFG of mass m and side a is wrapped by a square wire loop of perimeter 4a, carrying current I. The whole system is placed at frictionless horizontal surface in a uniform magnetic field `vecB=B_0hatj` as shown in fig. In this situation, normal force between horizontal surface and block passes through a point at a distance x from center. Choose correct statement (s).

A

The block must not topple if `Ilt (mg)/(aB_0)`

B

The block must not topple if `Ilt (mg)/(2aB_0)`

C

`x=a/4 if I=(mg)/(2aB_0)`

D

`x=a/4 if I=(mg)/(4aB_0)`

Text Solution

Verified by Experts

The correct Answer is:
(b,d)

Torque of magnetic field : `tau=MB_0=Ia^2B_0`
For rotation equilibrium: `tau=mgx implies Ia^2B_0=mgx`
`implies x=(Ia^2B_0)/(mg)`
For the block not to topple:
`xlta/2 implies Ilt(mg)/(2aB_0)`
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