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A small coil C with N=200 turns is mount...

A small coil C with N=200 turns is mounted on one end of a balance beam and introduced between the poles of an electromagnetic as shown in Fig. The area of the coils is `S=1cm^2`, the length of the right arm of the balance beam is l=30cm. When there is no current in the coil the balance is in equilibrium. On passing is a currentI=22mA through the coil, equilibrium is restored by putting an additional weight of mass m=60mg on the balance pan. Find the magnetic induction field (in terms of x`10^-1T`) between the poles of the electromagnetic assuming it to be uniform.

Text Solution

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The correct Answer is:
4

Magnetic torque `=NISB sin (vecS, vecB)NISB sin90^@`
Gravitational torque`=(Deltamxxg)l`
For equilibrium `NISB=Deltamgl implies Deltamgl//NIS`
`B=((60xx10^-6)xx9.8xx0.3)/(200xx22xx10^-3xx1xx10^-4)=4xx10^-1T`.
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