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A 10 cm length of wire with a mass of 20...

A 10 cm length of wire with a mass of 20g is attached frictionlessly to the vertical segments of a wire in which a current I flows. The surrounding has horizontal field `B=10^4G` and the vertical direction is shown in fig. What must be the current I (in A) to maintain the 10cm wire in an equilibrium position?

Text Solution

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The correct Answer is:
2
`B=10^4G=1T`
For equilibrium, magnetic force should be equal to weight of wire.
`IBl=mg implies Ixx1xx0.10=20xx10^-3xx10 implies I=2A`
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