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A metal wire PQ of mass 10g lies at rest...

A metal wire PQ of mass 10g lies at rest on two horizontal metal rails separated by 5cm as shown in Fig. A vertically downward magnetic field of magnitude 0.80T exist in the space. The resistance of the circuit is slowly decreased and it is found that when the resistance goes below `20.0Omega` the wire PQ starts sliding on the rails. The coefficient of friction between wires and rails is found. The coefficient of friction between wires and rails is found to be `n//25`. find n

Text Solution

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The correct Answer is:
3
`Ibl=mumg`
`implies 6/20xx0.8xx5/100=mu10/1000(10)`
`implies mu=0.12=3//25`
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