A wire `ABCDEF` ( with each side of length `L`) bent as shown in figure and carrying a current `I` is placed in a uniform magnetic induction `B` parallel to the positive ` y- direction `. The force experienced by the wire is ……….. In the ………. direction .

Explanation

We use the formula `vecF=I(veclxxvecB) implies F=ILBsin theta`
For sides FE and BA, the angle will be
`180^@ and 0^@`, respectively.
`:.F=0`
For sides DE and CB, the forces will be
ILB but opposite in directions, in +X and
-X direction, respectively.
The net force due to these two sides will
be zero.
The force due to current inside DC will be `ILB sin90^@=ILB` in
+Z direction (according to Fleming's left hand rule.)
So net force on the wire is ILB is positive z direction.