Two parallel wires in the plane of the paper are distance `X_(0)` apart. A point charge is moving with speed `u` between the wires in the same plane at a distance `X_(1)` from one of the wires. When the wires carry current of magnitude `I` in the same direction , the radfius of curvature of the path of the point charge is `R_(1)`. In contrast, if the currentsd `I` in the two wires have directions opposite to each other, the radius of curvature of the path is `R_(2)`. if `(X_(0))/(X_(1)) = 3`, the value of `( R _(1))/( R_(2))` is

Answer

3

Explanation

`X_1=(X_0)/3` and `X_2=(2X_0)/3`
`r=(m u)/(qB)`
Hence ratio of radian
`(R_1)/(R_2)=(B_2)/(B_1)`
Case `I`
`B_1=(mu_0I)/(2pi)(1/(x_1)-1/(x_2))=(mu_0I)/(2pi)(3/(x_0)-3/(2x_2))=(2mu_0I)/(4pix_0)`
Case `II`
`B_2=(mu_0I)/(2pi)(1/(x_1)+1/(x_2))=(9mu_0I)/(4pix_0) implies (R_1)/(R_2)=(B_2)/(B_1)=3`