A circuit `ABCD` is held perpendicular to the uinform magnetic field of `B = 5 xx 10^(-2)T` extending over the region `PQRS` and directed into the plane of the paper. The cicuit is moving out of the field at a uin form speed of `0.2 m s^(-1)` for `1.5 s`. During this time, the current in the `5 Omega` resistor is

Options

A. (a) `0.6mA from B to C`
B. (b) `0.9mA from B to C`
C. ( c) `0.9mA from C to B`
D. (d) `0.6mA from C to B`

Answer

A

Explanation

(a) `I = (Blv)/( R)`
`I = (5 xx 10^(-2) xx 0.3 xx 0.2)/(5)A = 0.6 mA`.
Area and flux are decreasing. So, current flows to increase the flux. Clearly, current should be clockwise. So, it flows from `B to C` through `5 Omega`.