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The radius of the circular conducting lo...

The radius of the circular conducting loop shown in is R. magnetic field is decreasing at a constant rate `alpha`. Resisitance per unit length of the loop is `rho`.
Then, the current in wire `AB` is (`AB` is one of the diameters)

A

(a) `(Ralpha)/(2rho) from A to B`

B

(b) `(Ralpha)/(2rho) from B to A`

C

( c) `(Ralpha)/(rho) from A to B`

D

(d) `0`

Text Solution

Verified by Experts

The correct Answer is:
D
( d) According to Lenz's law, emf of same magnitude in clockwise direction in the two loops into which the figure is divided. So, current is induced in the clockwise direction in the outer boundary but no current is there in wire `AB`.
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