A conducting loop rotates with constant angular velocity about its fixed diameter in a uniform magnetic field, whose direction is perpendicular to that fixed diameter.

Options

A. (a) The emf will be maximum at the moment when flux is zero
B. (b) The emf will be `0` at the moment when flux ismaximum
C. ( c) The emf will be maximum at the moment when plane of the loop is parallel to the magnetic field
D. (d) The phase difference between the flux and the emf `pi//2`

Answer

A, B, C, D

Explanation

(a,b,c,d): `phi = Bacos theta, theta = omegat`
`e = (-dphi)/(dt) = Baomega sin theta`
at `theta = (pi)/(2), phi = 0` and `e` is maximum. At `theta = 0, phi` is maximum and `e` is zero. Emf is maximum where `theta = (pi)/(2)` and for this plane of loop is parallel to magnetic field. Clearly phase difference between flux and emf is `pi//2`.