A square conductind loop, `20.0 cm` on a side placed in the same magnetic field as shown in Fig. 3.195, center of the magnetic field region, where `dB//dt = 0.035 T s^(-1)`.

The current induced in the loop if its resistance is `2.00 Omega` is

Options

A. (a) `2.50 xx 10^(-4) A`
B. (b) `4.35 xx 10^(-4) A`
C. ( c) `1.25 xx 10^(-4) A`
D. (d) `7.37 xx 10^(-4) A`

Answer

D

Explanation

(d) `I = (epsilon)/(R ) = (A)/(R )(dB)/(dt) = (L^(2))/(R )(dB)/(dt)`
`= ((0.20 m)^(2)(0.0350 T //s))/(1.90 Omega)`
`= 7.37 xx 10^(-4) A`