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A square wire loop of 10.0 cm side lies ...

A square wire loop of `10.0 cm` side lies at right angles to a uniform magnetic field of `7 T`. A `10 V` light bulb is in a series with the loop as shown in Fig. 3.125. The magnetic field decreasing steadily to zero over a time interval `Deltat`. For what value of `Deltat` (im ms), the bulb will shine with full brightness?

Text Solution

Verified by Experts

The correct Answer is:
7
Unduced emf should be equal to `10 V`
`e = A(dB)/(dt) `rarr` 10 = ((10)/(100))^(2)(7)/(Deltat) `rarr` Deltat = 7 ms`
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