The equation of the radical axis of the two circles represented by the equations, `|z-2|=3` and `|z-2-3i|=4` an the complex plane is

The centre of circle represented by |z + 1| = 2 |z - 1| in the complex plane is

The centre of circle represented by |z + 1| = 2 |z - 1| in the complex plane is

The centre of circle represented by |z + 1| = 2 |z - 1| in the complex plane is

The centre of circle represented by |z+1|=2|z-1| in the complex plane is

If z is a complex number satisfying the equation |z+i|+|z-i|=8, on the complex plane thenmaximum value of |z| is

Solve the equation |z| + z = (2 + i) for complex value of z.

Let z_1, z_2 be two complex numbers represented by points on the circle |z_1|= and and |z_2|=2 are then

Let z in C, the set of complex numbers. Thenthe equation,2|z+3i|-|z-i|=0 represents :

The equation of the plane through the line of intersection of the planes x-y+z+3=0 and x+y+2z+1=0 and parallel to x-axis is a) 2y-z=2 b) 2y+z=2 c) 4y+z=4 d) 4y-2z=3