Let `f(x)={(-x^3+log_2a, 0<=x<1),(3x,1<=x<=3)}`, the complete set of real values of `a` for which `f(x)` has smallest value at `x=1` is

Similar Questions

Explore conceptually related problems

Let f(x)={-x^(3)+log2b,0 =1} Then minimum value of b-11 for which f(x) has least value at x=1 is

Let f(x) = 2x^(2) - log x , then

Let f(x)=(e^(x)x cos x-x log_(e)(1+x)-x)/(x^(2)),x!=0 If f(x) is continuous at x=0, then f(0) is equal to

Let f(x)=a^(x)-x ln a,a>1. Then the complete set of real values of x for which f'(x)>0 is

Let f(x) = (e^x x cosx-x log_e(1+x)-x)/x^2, x!=0. If f(x) is continuous at x = 0, then f(0) is equal to

Let f(x) = ln(x-1)(x-3) and g(x) = ln(x-1) + ln(x-3) then,

Let f(x) = x log x + 3x . Then

Let f(x) = x^(.^(3)//_(2)) . Then, f'(0) = ?