The scale on a steel on a steel meter stick is calibrated at `15^@ C`. What is the error in the reading of `60 cm` at `27^@C` ? `alpha_(steel) =1.2 xx 10^-5 (.^@ C)^-1`.

The scale on a steel meter stick is calibrated at 15^@ C . What is the error in the reading of 60 cm at 27^@C ? alpha_(steel) =1.2 xx 10^-5 (.^@ C)^-1 .

A second's pendulum clock has a steel wire. The clock is calibrated at 20^@ C . How much time does the clock lose or gain in one week when the temperature is increased to 30^@ C ? alpha_(steel = 1.2 xx 10^-5(^@ C)^-1 .

A second's pendulum clock has a steel wire. The clock is calibrated at 20^@ C . How much time does the clock lose or gain in one week when the temperature is increased to 30^@ C ? alpha_(steel = 1.2 xx 10^-5(^@ C)^-1 .

A second's pendulum clock has a steel wire. The clock is calibrated at 20^@ C . How much time does the clock lose or gain in one week when the temperature is increased to 30^@ C ? alpha_(steel) = 1.2 xx 10^-5(^@C)^-1 .

A steel rod when measured with a zinc scale (alpha = 26 xx 10^(-6)//^@C) appears to be 1 m long when both rods are at 20^@C . If the zinc scale was graduated at 0^@C , what is the true length of the steel rod at 0^@C ? alpha for steel = 12 xx 10^(-6)//^@C .

A second's pendulum clock has a steel wire. The clock is calibrated at 20^@ C . How much time does the clock lose or gain in one week when the temperature is increased to 30^@ C ? alpha_(steel) = 1.2 xx 10^(-5).^@C^(-1) .

A steel rular exactly 20 cm long is graguated to give correct measurements at 20^@C . (a) Will it give readings that are too long or too short at lower temperatures? (b) What will be that actual length of the rular when it is used in the desert at a temperature of 40^@ C ? alpha_(steel = 1.2 xx 10^-5(.^@ C)^-1 .

A steel rular exactly 20 cm long is graduated to give correct measurements at 20^@C . (a) Will it give readings that are too long or too short at lower temperatures? (b) What will be that actual length of the rular when it is used in the desert at a temperature of 40^@ C ? alpha_(steel) = 1.2 xx 10^-5(.^@ C)^-1 .

A steel rular exactly 20 cm long is graduated to give correct measurements at 20^@C . (a) Will it give readings that are too long or too short at lower temperatures? (b) What will be that actual length of the rular when it is used in the desert at a temperature of 40^@ C ? alpha_(steel = 1.2 xx 10^-5(.^@ C)^-1 .

A steel tape is correctly calibrated at 20^(@)C and is used to measure the length of a table at 30^(@)C . Find the percentage error in the measurement of length. [alpha_(steel) = 11 xx 10^(-5)//.^(@)C]