If `a_0,a_1,a_3,a_4........` are in AP with common difference `d` where `d !=0,1,-1`, then the value of `|(a_1a_2, a_1, a_0),(a_2a_3,a_2,a_1),(a_3a_4,a_3,a_2)|` is

If a_1,a_2,a_3,……………….. are in A.P., then the value of: {:|(a_1,a_2,1),(a_2,a_3,1),(a_3,a_4,1)| is equal to

Evaluate: /_\ |[1+a_1, a_2, a_3],[a_1, 1+a_2, a_3],[a_1, a_2, 1+a_3]|

Evaluate: /_\ |[1+a_1, a_2, a_3],[a_1, 1+a_2, a_3],[a_1, a_2, 1+a_3]|

Evaluate: /_\ |[1+a_1, a_2, a_3],[a_1, 1+a_2, a_3],[a_1, a_2, 1+a_3]|

If a_1, a_2,a_3, ,a_n is an A.P. with common difference d , then "tan"[tan^(-1)(d/(1+a_1a_2))+tan^(-1)(d/(1+a_2a_3))+...+tan^(-1)(d/(1+a_(n-1)a_n))]=

If a_1,a_2,a_3,a_4 are the coefficients of 2nd, 3rd, 4th and 5th terms of (1+x)^n respectively then (a_1)/(a_1+a_2) , (a_2)/(a_2+a_3),(a_3)/(a_3+a_4) are in

If a_1,a_2,a_3,………….a_12 are in A.P. and /_\_1 =|(a_1a_5, a_1,a_2),(a_2a_6,a_2,a_3),(a_3a_7,a_3,a_4)|, |(a_2a_10, a_2,a_3),(a_3a_11,a_3,a_4),(a_4_12,a_4,a_5)| then /_\_1:/_\_2= (A) 1:2 (B) 2:1 (C) 1:1 (D) none of these