A string 1 m long with mass 0.1 g `cm^(-1)` is under a tension of 400 N.Find is fundamental frequency of vibration.

In law of tension , the fundamental frequency of vibrating string is

In law of tension, the fundamental frequency of vibrating string is

The mass of string (M) = 2 . 5 g , length (l) = 25 cm and tension (T) = 25 N . Determine the fundamental frequency of transverse vibration in the string .

A 100 cm long wire of mass 40 g supports a mass of 1.6 kg as shown in figure . Find the fundamental frequency of the portion of the string between the wall and the pulley. Take g=10m//s^(2) .

A string vibrates in its first normal mode with a frequency of 220 vibrations //s . The vibrating segment is 70.0 cm long and has a mass of 1.20g. (a) Find the tension in the string. (b) Determine the frequency of vibration when the string vibrates in three segments.

A string vibrates in its first normal mode with a frequency of 220 vibrations //s . The vibrating segment is 70.0 cm long and has a mass of 1.20g. (a) Find the tension in the string. (b) Determine the frequency of vibration when the string vibrates in three segments.

A one meter long string of mass 4.9 xx 10^(-4) kg is held under a tension of 19.6 N. IF the string vibrates in one segment, then the frequency of vibration will be

A steel piano wire 0.5 m long has a total mass of 0.01 kg and is stretched with a tension of 800 N. The frequency, when it vibrates in its fundamental mode, is

A steel piano wire 0.5 m long has a total mass of 0.01 kg and is stretched with a tension of 800 N. The frequency, when it vibrates in its fundamental mode, is