In a triangle ABC, `a-2b +c=0`.The value of `cot(A/2)cot(C/2)` is

In a triangle ABC if b+c=3a then find the value of cot(B/2)cot(C/2)

In a triangle ABC if b+c=3a then find the value of cot(B/2)cot(C/2)

In a triangle ABC if b+c=3a then find the value of cot(B/2)cot(C/2)

In a triangle ABC, if 3a = b+c, then the value of cot ""(B)/(2) cot ""C/2 is-

In a triangle ABC if b+c=3a then find the value of cot((B)/(2))cot((C)/(2))

In triangle ABC, the value of (cot""A/2cot ""B/2-1)/(cot ""A/2 cot ""B/2) is

In triangle ABC the value of ( cot A/2 cot ""B/2 -1)/( cot""A/2 cot""B/2) is

In triangle ABC , "tan"(A)/(2),"tan"(B)/(2),"tan"(C)/(2) are in H.P ., then the value of "cot"(A)/(2)xx"cot"(C)/(2) is equal to

In a triangle ABC,if a cot A+b cot B+c cot C=