Given the function `f:x->5 -4x` find the following value of f : a) f(0) b) f(-2) c) f(-3/2)

A graph representing the function f(x) is given in figure it is clear that f(9)=2 . Find the following values of the function (a)f(0) (b)f(7) (c)f(2) (d)f(10)

Given the function f(x) = 2x + 7. Find f(0), f(5), f(7).

Given the function f(x) = 2x + 7. Find f(0), f(5), f(7).

If f(x) is a real valued function, then which of the following is injective function ? (i) f(x) = x^(5) (ii) f(x) = x + sin x (iii) f(x) = x^(2) (iv) f(x) = e^(x) (v) f(x) = x^(3) + x^(2) + 4x + 4

If f(x) is a real valued function, then which of the following is injective function ? (i) f(x) = x^(5) (ii) f(x) = x + sin x (iii) f(x) = x^(2) (iv) f(x) = e^(x) (v) f(x) = x^(3) + x^(2) + 4x + 4

Following questions are based on the given information for the following functions f (x) f(x) =2bx +f(-x)," if " x lt 0 f(x)=a, " if "x =0 f(x)=b+c-2cx +f(x-1)," if "x gt 0 f(-19) equals:

A real valued function f(x) satisfies the functional equation f(x-y) = f(x) f(y) - f(a-x) f(a+y) , where a is a given constant and f(0)=1 , f(2a-x) =?

A real valued function f(x) satisfies the functional equation f(x-y) = f(x) f(y) - f(a-x) f(a+y) , where a is a given constant and f(0)=1 , f(2a-x) =?