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Let P""=""(-1,""0),""Q""=""(0,""0)""a...

Let `P""=""(-1,""0),""Q""=""(0,""0)""a n d""R""=(3,""3sqrt(3))` be three points. The equation of the bisector of the angle PQR (1) `sqrt(3)x+y=0` (2) `x+(sqrt(3))/2y=0` (3) `(sqrt(3))/2x+y=0` (4) `x+sqrt(3)y=0`

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To find the equation of the angle bisector of triangle PQR formed by the points P(-1, 0), Q(0, 0), and R(3, 3√3), we will follow these steps: ### Step 1: Find the slopes of lines PQ and QR. 1. **Slope of line PQ**: - Points: P(-1, 0) and Q(0, 0) - Slope (m1) = (y2 - y1) / (x2 - x1) = (0 - 0) / (0 - (-1)) = 0 ...
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Knowledge Check

  • Let P = (-1,0), Q = (0,0) and R = (3, 3sqrt(3)) be three point. The equation of the bisector of the angle PQR is:

    A
    `sqrt(3)/2 x + y=0`
    B
    `x + sqrt(3)y =0`
    C
    `sqrt(3)x + y =0`
    D
    `x + sqrt(3)/2 y = 0`

  • Let P (-1, 0), Q (0, 0) and R (3, 3sqrt3 ) be three points. Then, the equation of the bisector of /_PQR is

    A
    `sqrt3/2 x+y=0`
    B
    `x+sqrt3 y=0`
    C
    `sqrt3 x+y=0`
    D
    `x+sqrt3/2 y=0`

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    Let P=(-1,0),Q(0,0) and R=(3,3sqrt(3)) be three points. Then the equation of the bisector of the angle PQR is

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