A metal oxide has the formula `Z_(2)O_(3)`. It can be reduced by hydrogen to give free metal and water. 0.1596 g of the metal requires 6 mg of hydrogen for complete reduction. The atomic mass of the metal is:

A metal oxide has the formula Z_(2)O_(3) . It can be reduced by hydrogen to give free metal and water . 0.1596 g of the metal oxide requires 6 mg of hydrogen for complete reduction . The atomic weight of the metal is

A metal oxide has the formula Z_(2)O_(3) . It can be reduced by hydrogen to give free metal and water . 0.1596 g of the metal oxide requires 6 mg of hydrogen for complete reduction . The atomic weight of the metal is

A metal oxide has the formula X_2O_3 . It can be reduced by hydrogen to give free metal and water. 0.1596g of metal oxide requires 6mg of hydrogen for complete reduction. The atomic mass of the metal (in amu) is :

A metal oxide has the formula X_2O_3 . It can be reduced by hydrogen to give free metal and water. 0.1596g of metal oxide requires 6mg of hydrogen for complete reduction. The atomic mass of the metal (in amu) is :

A metal oxide has the formula X_(2)O_(3) . It can be reduced by hydrogen to give free metal and water. 0.159g of metal oxide requires 6 mg of hydrogen for complete reduction. The atomic mass of metal is amu is