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If sin^(-1)(x/5)+cose c^(-1)(5/4)=pi/2 ...

If `sin^(-1)(x/5)+cose c^(-1)(5/4)=pi/2` then the value of x is: (1) 1 (2) 3 (3) 4 (4) 5

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To solve the equation \( \sin^{-1}\left(\frac{x}{5}\right) + \cos^{-1}\left(\frac{5}{4}\right) = \frac{\pi}{2} \), we can follow these steps: ### Step 1: Use the identity for inverse trigonometric functions We know that: \[ \cos^{-1}(y) = \frac{\pi}{2} - \sin^{-1}(y) \] Thus, we can rewrite \( \cos^{-1}\left(\frac{5}{4}\right) \) as: ...
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Knowledge Check

  • If sin^(-1)(x/5) + cosec^(-1) (5/4) = pi/2 , then the value of x is

    A
    1
    B
    3
    C
    4
    D
    5
  • If sin^(-1) ((x)/(5))+ cosec^(-1) ((5)/(4))=(pi)/(2) , then the value of x is

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    4
    D
    5
  • If sin^(-1)"" x/5 + cosec^(-1)"" 5/4 = pi/2 " then " x=

    A
    4
    B
    5
    C
    1
    D
    3
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