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An increase in intensity level of 1 dB i...

An increase in intensity level of 1 dB implies an increase in density of (given anti `log_(10)0.1=1.2589`)

A

`1%`

B

`3.01%`

C

`26%`

D

`0.1%`

Text Solution

Verified by Experts

The correct Answer is:
C
Intensity level is decibel is given by
`L=10log_(10)((I)/(I_0))`
`L+1=10log_(10)((I_1)/(I_0))`
Subtracting, `1=10log_(10)((I_1)/(I_0))-10log_(10)((I)/(I_0))`
or `(1)/(10)=log_(10)((I_1)/(I))`
or `0.1=log_(10)((I_1)/(I))`
or `(I_1)/(I)=1.26`
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