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In the binomial expansion of (a-b)^n , n...

In the binomial expansion of `(a-b)^n , ngeq5,` the sum of 5th and 6th terms is zero, then `a/b` equals (1) `5/(n-4)` (2) `6/(n-5)` (3) `(n-5)/6` (4) `(n-4)/5`

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Knowledge Check

  • In the binomial expansion of (a-b)^(n), n ge5 , the sum of 5th and 6th terms is zero, then (a)/(b) equals:

    A
    `(5)/(n-4)`
    B
    `(6)/(n-5)`
    C
    `(n-5)/(6)`
    D
    `(n-4)/(5)`

  • In the binomial expansion of (a-b)^(n), n le 5 the sum of the 5th and 6th terms is zero. Then (a)/(b) equals

    A
    `(n-5)/(6)`
    B
    `(n-4)/(5)`
    C
    `(5)/(n-4)`
    D
    `(6)/(n-5)`

  • In the binomial expansion of (a - b)^(n) , n ge 5 , the sum of the 5^(th) and 6^(th) terms is zero. Then, a//b equals

    A
    `(n-5)/(6)`
    B
    `(n- 4) /(5)`
    C
    `(5)/(n-4)`
    D
    `(6)/(n-5)`

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