Home
Class 12
MATHS
The equation of tangent to the curve y=b...

The equation of tangent to the curve `y=b^(-x//a)` at the point where it crosses Y-axis is

Promotional Banner

Similar Questions

Explore conceptually related problems

The equation of tangent to the curve y=be^(-x//a) at the point where it crosses Y-axis is

The equation of the tangent to the curve y=be^(-x/a) at the point where it crosses the y-axis is a)(x)/(a)-(y)/(b)=1( b) ax+by=1 c)ax -by=1( d) (x)/(a)+(y)/(b)=1

The equation of the tangent to the curve y=b e^(-x//a) at the point where it crosses the y-axis is x/a-y/b=1 (b) a x+b y=1 a x-b y=1 (d) x/a+y/b=1

The equation of the tangent to the curve y=b e^(-x//a) at the point where it crosses the y-axis is (a)x/a-y/b=1 (b) a x+b y=1 (c)a x-b y=1 (d) x/a+y/b=1

The equation of the tangent to the curve y=b e^(-x//a) at the point where it crosses the y-axis is a)x/a-y/b=1 (b) a x+b y=1 c)a x-b y=1 (d) x/a+y/b=1

The equation of the tangent to the curve y=b e^(-x//a) at the point where it crosses the y-axis is (a)x/a-y/b=1 (b) a x+b y=1 (c)a x-b y=1 (d) x/a+y/b=1

The equation to the tangent to the curve y=be^(x//a) at the point where x=0 is

The equation to the tangent to the curve y = be ^(-x/a) at the point where it crosses the y-axis is