12. Let f: R10. o.) be such that lim f(x) existsandlim (f(x)) =95 Vix-51= 0. Then lim f(x) equals.(2) 0(c) 2(b) 1M 3[2011]

Let f :R to [0,oo) be such that lim_(xto3) f(x) exists and lim_(x to 3) ((f(x))^2-4)/sqrt(|x-3|)=0 . Then lim_(x to 3) f(x) equals

Let f:RtoR be such that f(1)=3 and f'(1)=6 . Then lim_(xto0)[(f(1+x))/(f(1))]^(1//x) equals

Let f:RtoR be such that f(1)=3 and f'(1)=6 . Then lim_(xto0)[(f(1+x))/(f(1))]^(1//x) equals

Let f : R to R be such that f (1) = 3 and f'(1) = 6. Then, lim_( x to 0) [(f(1+x))/(f(1))]^(1//x) equals

Let f:R rarr[0,oo) be such that lim_(x rarr5)f(x) exists and lim_(x rarr5)([f(x)]^(2)-9)/(sqrt(|x-5|))=0 .then,lim_(x rarr6)f(x) equals to

Let f: R rarr [10,oo) be such that lim_(x rarr 5)f(x) exists and lim_(x rarr 5) ((f (x))^(2)-9)/(sqrt(|x-5|))=0 . Then lim_(x rarr 5) f(x) equals :

Let f : R rarr [10, oo) be such that lim_(x rarr 5) f(x) exists and lim_(x rarr 5) ((f (x))^(2)-9)/(sqrt(|x-5|))=0 . Then lim_(x rarr 5) f(x) equals :

Let f :R to R be a function such that f(x) = x^3 + x^2 f' (0) + xf'' (2) , x in R Then f(1) equals:

f:RtoR such that f(2)=5 and f'(2)=10 then lim_(xto0) ((f(2+x))/(f(2)))^(1//x) is equal to: