Home
Class 12
MATHS
ABC is a right angled triangle of which ...

ABC is a right angled triangle of which A is the right angle, BD is drawn perpendicular to BC meets CA produced in D. If AB = 12, AC = 16, BC = 20, then BD =

Promotional Banner

Similar Questions

Explore conceptually related problems

ABC is a right-angled triangled, right angled at A*AD is drawn perpendicular to BC from A . Then AB^2 is equal to

DeltaABC is a right angle triangle (right angled at B), BD is perpendicular to AC. If AC = 16 cm, BC = 12 cm, find the length of CD.

ABC is right triangle right angled at B.If BD is the length of the perpendicular drawn from B to AC then

ABC is a right angled triangle right angled at C. CD is perpendicular on the hypotenuse AB. Prove that (AC^2)/(BC^2)=(AD)/(DB)

In a right triangle ABC, right angled at A, AD is drawn perpendicular to BC. Prove that: AB^(2)-BD^(2)= AC^(2)-CD^(2)

In a right triangle ABC, right angled at A, AD is drawn perpendicular to BC. Prove that: AB^(2)-BD^(2)= AC^(2)-CD^(2)

ABC is right angle triangle where AD is perpendicular on hypotenuse BC. If AC = 2 AB find BD.

∆ABC is a right angled triangle right angled at A and AD _|_ BC . Prove that AD^2 = BD.CD .