Two aeroplanes I and II bomb a target in succession. The probabilities of I and II scoring a hit correctly are 0.3 and 0.2, respectively. The second plane will bomb only if the first misses the target. The probability that the target is hit by the second plane is (A) `0.06`                                                     (B) `0.14` (C) `7/22`                                                       (D) `0.7`

Explanation

To solve the problem, we need to find the probability that the target is hit by the second plane (Plane II), given that the first plane (Plane I) missed the target.

Let's denote:
- \( P(H_1) \) = Probability that Plane I hits the target = 0.3
- \( P(M_1) \) = Probability that Plane I misses the target = \( 1 - P(H_1) = 1 - 0.3 = 0.7 \)
- \( P(H_2) \) = Probability that Plane II hits the target = 0.2
- \( P(M_2) \) = Probability that Plane II misses the target = \( 1 - P(H_2) = 1 - 0.2 = 0.8 \)

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