Derive a method to find separate equation of pair of lines given by `ax^2+2hxy+by^2+2gx+2fy+c=0`

Find dy/dx if ax^2+2hxy+by^2+2gx+2fy+c=0

Find dy/dx if ax^2+2hxy+by^2+2gx+2fy+c=0

Find dy/dx if ax^2+2hxy+by^2+2gx+2fy+c=0

The square of the distance between the origin and the point of intersection of the lines given by ax^(2)+2hxy+by^(2)+2gx+2fy+c=0 , is

The square of the distance between the origin and the point of intersection of the lines given by ax^(2)+2hxy+by^(2)+2gx+2fy+c=0 , is

Find dy/dx : ax^2+2hxy+by^2+2gx+2fy+c = 0

Find the equation of the pair of lines passing through the origin and perpendicular to the pair of lines ax^(2)+2hxy+by^(2)+2gx+2fy+c=0

Show that product of the perpendicular distances from origin to pair of lines represented by ax^(2)+2hxy+by^(2)+2gx+2fy+c=0 is (|c|)/(sqrt((a-b)^(2)+4h^(2)))