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The only possibility of heat flow in a t...


The only possibility of heat flow in a thermos flask is through its cork which is `75cm^2` in area and 5 cm thick its thermal conductivity is `0.0075 cal//cm-s-^@C`. The outside temperature is `40^@C` and latent heat of ice is `80 cal//g`. Time taken by 500 g of ice at `0^@C` in the flask to melt into water at `0^@C` is `

A

2.47 h

B

4.27 h

C

7.42 h

D

4.72 h

Text Solution

Verified by Experts

The correct Answer is:
A

`mL=(KaDeltathetat)/(Deltax)`
`implies=500xx80=(0.0075xx75xx(40-0)t)/(5)`
`impliest=8.9xx10^3s=2.47h`
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The only possibility of heat flow in a thermos flask is through its cork which is 75 cm^(2) in area and 5 cm thick. Its thermal conductivity is 0.0075 cal//cm sec^(@)C . How lolng will 500 g of ice at 0^(@)C in thermos flask will is 40^(@)C and latent heat of ise is 80 cal.//gram .

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