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The wavelength of maximum energy release...

The wavelength of maximum energy released during an atomic axplosion was `2.93xx10^(-10)m`. Given that Wien's constant is `2.93xx10^(-3)m-K`, the maximum temperature attained must be of the order of

A

`10^(-7)`K

B

`10^7K`

C

`10^(-13)K`

D

`5.86xx10^7K`

Text Solution

Verified by Experts

The correct Answer is:
B
From Wien's displacement law `lamda_mT=b`
`:. T=(b)/(lamda_m)=(2.93xx10^-3)/(2.93xx10^(-10))=10^7K`
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