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A rod of length l and cross sectional ar...

A rod of length l and cross sectional area A has a variable conductivity given by `K=alphaT`, where `alpha` is a positive constant T is temperatures in Kelvin. Two ends of the rod are maintained at temperatures `T_1` and `T_2(T_1gtT_2)`. Heat current flowing through the rod will be

A

`(A alphaT_1^2-T_2^2)/(l)`

B

`(A alpha T_1^2+T_2^2)/(l)`

C

`(A alpha T_1^2+T_2^2)/(3l)`

D

`(A alpha T_1^2-T_2^2)/(2l)`

Text Solution

Verified by Experts

The correct Answer is:
D

Heat current:
`i=-kA(dT)/(dx)`
`idx=-kAdT`
`iint_0^ldx=-Aalphaint_(T_1)^(T_2)TdT`
`il=Aalpha((T_2^2-T_1^2))/(2)impliesi=(Aalpha(T_1^2-T_2^2))/(2l)`
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