A mass m of lead shot is placed at the b...

A mass m of lead shot is placed at the bottom of a vertical cardboard cylinder that is 1.5 m long and closed at both ends. The cylinder is suddenly inverted so that the shot falls 1.5 m If this procces is repeated quickely 100 times, auuming no heat is dissipated or lost, the temperature of the shot will increase by (specific heat of lead`=0.03 cal//g^@C`)

`5^@C`

`7.3^@C`

`11.3^@C`

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The correct Answer is:

Specific heat of lead`=0.03 kcal//kg^(@)C`. Gravitational potential energy is converted into thermal energy which is absorbed by the lead shot. If `T_0` is the rise in temperature of the shot, then
`(100)[mgh]=(mxxsxxT)J`
`T=(100xxgxxh)/(Js)=(100xx9.8xx1.5)/(0.03xx4.18xx10^3).^(@)C=11.3^@C`

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