A liquid of density `0.85 g//cm^(3)` flows through a calorimeter at the rate of `8.0 cm^(2)//s`. Heat is added by means of a 250 W electric heating coil and a temperature difference of `15^@C` is established in steady state conditions between the inflow and the outflow points of the liquid. The specific heat for the liquid will be

Options

A. `0.6kcal//kgK`
B. `0.3kcal//kgK`
C. `0.5kcal//kgK`
D. `0.4 kcal//kgK`

Answer

A

Explanation

This is a problem on flow calorimeter used to measure specific heat of a liquid.
Amount of heat supplied to the water per second by the heating coil`=Q_S=250J`
`=(250)/(4186)kcal`
The volume of liquid flowing out per second `=8.0cm^3=8xx10^6m^3`
Mass of this liquid`=(0.85)xx1000xx8xx10^-6kg`
Temperature rise of this mass of liquid`=15^@C`
hence, `(250)/(4186)=mst=0.85xx8xx10^-3xxsxx15`
hence, `s=(250xx10^3)/(4186xx0.85xx8xx15)=0.6 kcal//kgK`