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A steel ball of mass 0.1 kg falls freely...

A steel ball of mass 0.1 kg falls freely from a height of 10 m and bounces to a height of 5.4 m from the ground. If the dissipated energy in this process is absorbed by the ball, the rise in its temperature is (specific heat of steel `=460 K//kg^(@)//C,g=10 m//s^(2)`)

A

`0.01^@C`

B

`0.1^@C`

C

`1^@C`

D

`1.1^@C`

Text Solution

Verified by Experts

The correct Answer is:
B
Loss in energy `=mg(h-h')`
`=0.1xx10xx(10-5.4)`
`=4.6J`
Now, `4.6J=ms Delta theta`
`=0.1xx460xxDelta theta`
`Delta theta=0.1^@C`
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Knowledge Check

  • A brass sphere of mass 0.2kg falls freely from a height of 20m and bounces to a height of 8m from the ground. If the dissipated energy in this process is absorbed by the sphere the eise in its temperature is (specific heat of brass =360 J kg^(-1)K^(-1) , g=10ms^(-2) )

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